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8x^2-13x=-3/2
We move all terms to the left:
8x^2-13x-(-3/2)=0
We get rid of parentheses
8x^2-13x+3/2=0
We multiply all the terms by the denominator
8x^2*2-13x*2+3=0
Wy multiply elements
16x^2-26x+3=0
a = 16; b = -26; c = +3;
Δ = b2-4ac
Δ = -262-4·16·3
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-22}{2*16}=\frac{4}{32} =1/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+22}{2*16}=\frac{48}{32} =1+1/2 $
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